Simplify:

$\frac{7^8 × 12^8}{14^8 × 6^8}$

$\frac{7^8 × 12^8}{14^8 × 6^8}$

Using Exponent Product rule $(a × b)^n$ can be written as $a^n × b^n$

$12^8$ can be written as $2^8 × 6^8$ and $14^8$ can be written as $2^8 × 7^8$

⇒ $\frac{7^8 × 2^8 × 6^8}{2^8 × 7^8 × 6^8}$

⇒ $\frac{7^{8-8} × 2^{8-8} × 6^{8-8}}{1}$

⇒ ${7^{8-8} × 2^{8-8} × 6^{8-8}}$

⇒ ${7^0 × 2^0 × 6^0}$

⇒ $1$